311440304013413 has 2 divisors, whose sum is σ = 311440304013414. Its totient is φ = 311440304013412.

The previous prime is 311440304013401. The next prime is 311440304013427. The reversal of 311440304013413 is 314310403044113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 289852599903364 + 21587704110049 = 17025058^2 + 4646257^2 .

It is a cyclic number.

It is not a de Polignac number, because 311440304013413 - 2¹⁰ = 311440304012389 is a prime.

It is a super-3 number, since 3×311440304013413³ (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 311440304013413.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311440304013473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155720152006706 + 155720152006707.

It is an arithmetic number, because the mean of its divisors is an integer number (155720152006707).

Almost surely, 2^{311440304013413} is an apocalyptic number.

It is an amenable number.

311440304013413 is a deficient number, since it is larger than the sum of its proper divisors (1).

311440304013413 is an equidigital number, since it uses as much as digits as its factorization.

311440304013413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20736, while the sum is 32.

Adding to 311440304013413 its reverse (314310403044113), we get a palindrome (625750707057526).

The spelling of 311440304013413 in words is "three hundred eleven trillion, four hundred forty billion, three hundred four million, thirteen thousand, four hundred thirteen".