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31144121443439 is a prime number
BaseRepresentation
bin1110001010011010011100…
…10010111010010001101111
311002021100102101001002020122
413011031032102322101233
513040231130042142224
6150123224544235155
76363042235243514
oct705151622722157
9132240371032218
1031144121443439
119a181696a1594
1235abb3330babb
13144bb550cc3b4
1479955254930b
153901e3ec515e
hex1c534e4ba46f

31144121443439 has 2 divisors, whose sum is σ = 31144121443440. Its totient is φ = 31144121443438.

The previous prime is 31144121443417. The next prime is 31144121443441. The reversal of 31144121443439 is 93434412144113.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 31144121443439 - 216 = 31144121377903 is a prime.

It is a super-3 number, since 3×311441214434393 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Sophie Germain prime.

Together with 31144121443441, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 31144121443439.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31144121443469) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15572060721719 + 15572060721720.

It is an arithmetic number, because the mean of its divisors is an integer number (15572060721720).

Almost surely, 231144121443439 is an apocalyptic number.

31144121443439 is a deficient number, since it is larger than the sum of its proper divisors (1).

31144121443439 is an equidigital number, since it uses as much as digits as its factorization.

31144121443439 is an evil number, because the sum of its binary digits is even.

The product of its digits is 497664, while the sum is 44.

The spelling of 31144121443439 in words is "thirty-one trillion, one hundred forty-four billion, one hundred twenty-one million, four hundred forty-three thousand, four hundred thirty-nine".