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31174699613221 is a prime number
BaseRepresentation
bin1110001011010011011001…
…11001010111110000100101
311002101021100102021001110101
413011221230321113300211
513041231241100110341
6150145243112424101
76365204055350533
oct705515471276045
9132337312231411
1031174699613221
119a2a13023308a
1235b5a479a8031
1314519b91b8898
1479ac13697153
15390dd3758831
hex1c5a6ce57c25

31174699613221 has 2 divisors, whose sum is σ = 31174699613222. Its totient is φ = 31174699613220.

The previous prime is 31174699613179. The next prime is 31174699613231. The reversal of 31174699613221 is 12231699647113.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 24857952350625 + 6316747262596 = 4985775^2 + 2513314^2 .

It is a cyclic number.

It is not a de Polignac number, because 31174699613221 - 217 = 31174699482149 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31174699613231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15587349806610 + 15587349806611.

It is an arithmetic number, because the mean of its divisors is an integer number (15587349806611).

Almost surely, 231174699613221 is an apocalyptic number.

It is an amenable number.

31174699613221 is a deficient number, since it is larger than the sum of its proper divisors (1).

31174699613221 is an equidigital number, since it uses as much as digits as its factorization.

31174699613221 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2939328, while the sum is 55.

The spelling of 31174699613221 in words is "thirty-one trillion, one hundred seventy-four billion, six hundred ninety-nine million, six hundred thirteen thousand, two hundred twenty-one".