Base | Representation |
---|---|
bin | 100011011110001011011100… |
… | …0110100111101110001000111 |
3 | 1111220201221221001200011222122 |
4 | 1012330112320310331301013 |
5 | 311343442012012011101 |
6 | 3023331512532520155 |
7 | 122502023306054426 |
oct | 10674267064756107 |
9 | 1456657831604878 |
10 | 312011000110151 |
11 | 904641384a7951 |
12 | 2abb19a478005b |
13 | 10513684a5a204 |
14 | 57095ad3132bd |
15 | 26111c734151b |
hex | 11bc5b8d3dc47 |
312011000110151 has 2 divisors, whose sum is σ = 312011000110152. Its totient is φ = 312011000110150.
The previous prime is 312011000110127. The next prime is 312011000110177. The reversal of 312011000110151 is 151011000110213.
It is a weak prime.
It is an emirp because it is prime and its reverse (151011000110213) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 312011000110151 - 242 = 307612953599047 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312011000110111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156005500055075 + 156005500055076.
It is an arithmetic number, because the mean of its divisors is an integer number (156005500055076).
Almost surely, 2312011000110151 is an apocalyptic number.
312011000110151 is a deficient number, since it is larger than the sum of its proper divisors (1).
312011000110151 is an equidigital number, since it uses as much as digits as its factorization.
312011000110151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 30, while the sum is 17.
Adding to 312011000110151 its reverse (151011000110213), we get a palindrome (463022000220364).
The spelling of 312011000110151 in words is "three hundred twelve trillion, eleven billion, one hundred ten thousand, one hundred fifty-one".
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