Search a number
-
+
31201243477 is a prime number
BaseRepresentation
bin11101000011101111…
…010011000101010101
32222112110122101122021
4131003233103011111
51002400004242402
622200022533141
72153124123265
oct350357230525
988473571567
1031201243477
111226131a038
1260692971b1
132c33203561
14171dbbd7a5
15c2930cd37
hex743bd3155

31201243477 has 2 divisors, whose sum is σ = 31201243478. Its totient is φ = 31201243476.

The previous prime is 31201243397. The next prime is 31201243481. The reversal of 31201243477 is 77434210213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31020367876 + 180875601 = 176126^2 + 13449^2 .

It is an emirp because it is prime and its reverse (77434210213) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 31201243477 - 27 = 31201243349 is a prime.

It is a super-2 number, since 2×312012434772 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31201243277) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15600621738 + 15600621739.

It is an arithmetic number, because the mean of its divisors is an integer number (15600621739).

Almost surely, 231201243477 is an apocalyptic number.

It is an amenable number.

31201243477 is a deficient number, since it is larger than the sum of its proper divisors (1).

31201243477 is an equidigital number, since it uses as much as digits as its factorization.

31201243477 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28224, while the sum is 34.

The spelling of 31201243477 in words is "thirty-one billion, two hundred one million, two hundred forty-three thousand, four hundred seventy-seven".