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312020444133239 is a prime number
BaseRepresentation
bin100011011110001111110101…
…1101111000011011101110111
31111220202212022020021021011112
41012330133223233003131313
5311344120332144230424
63023340114015025235
7122502506322662432
oct10674375357033567
91456685266237145
10312020444133239
11904681443a2206
122abb379b50b21b
131051452b4c385a
145709c276ac819
15261157b4ca60e
hex11bc7ebbc3777

312020444133239 has 2 divisors, whose sum is σ = 312020444133240. Its totient is φ = 312020444133238.

The previous prime is 312020444133199. The next prime is 312020444133241. The reversal of 312020444133239 is 932331444020213.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 312020444133239 - 212 = 312020444129143 is a prime.

It is a super-2 number, since 2×3120204441332392 (a number of 30 digits) contains 22 as substring.

Together with 312020444133241, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 312020444133196 and 312020444133205.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (312020444133259) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156010222066619 + 156010222066620.

It is an arithmetic number, because the mean of its divisors is an integer number (156010222066620).

Almost surely, 2312020444133239 is an apocalyptic number.

312020444133239 is a deficient number, since it is larger than the sum of its proper divisors (1).

312020444133239 is an equidigital number, since it uses as much as digits as its factorization.

312020444133239 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 373248, while the sum is 41.

The spelling of 312020444133239 in words is "three hundred twelve trillion, twenty billion, four hundred forty-four million, one hundred thirty-three thousand, two hundred thirty-nine".