Base | Representation |
---|---|
bin | 100011011110010100110100… |
… | …0000100101101110111011110 |
3 | 1111220210212212021000122121010 |
4 | 1012330221220010231313132 |
5 | 311344304213222340220 |
6 | 3023345041230320050 |
7 | 122503335016250202 |
oct | 10674515004556736 |
9 | 1456725767018533 |
10 | 312031120121310 |
11 | 90471722746047 |
12 | 2abb587a959026 |
13 | 10515540263b65 |
14 | 570a55b518b02 |
15 | 26119a38b61e0 |
hex | 11bca6812ddde |
312031120121310 has 128 divisors (see below), whose sum is σ = 773230881886848. Its totient is φ = 80535896064000.
The previous prime is 312031120121291. The next prime is 312031120121339. The reversal of 312031120121310 is 13121021130213.
It is a super-3 number, since 3×3120311201213103 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 122523120 + ... + 125043900.
It is an arithmetic number, because the mean of its divisors is an integer number (6040866264741).
Almost surely, 2312031120121310 is an apocalyptic number.
312031120121310 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 312031120121310, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (386615440943424).
312031120121310 is an abundant number, since it is smaller than the sum of its proper divisors (461199761765538).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
312031120121310 is a wasteful number, since it uses less digits than its factorization.
312031120121310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2521630.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 312031120121310 its reverse (13121021130213), we get a palindrome (325152141251523).
The spelling of 312031120121310 in words is "three hundred twelve trillion, thirty-one billion, one hundred twenty million, one hundred twenty-one thousand, three hundred ten".
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