Base | Representation |
---|---|
bin | 1110001100001000110111… |
… | …00110001100100010011011 |
3 | 11002111000102121212020121002 |
4 | 13012010123212030202123 |
5 | 13042214031000344344 |
6 | 150210351054135215 |
7 | 6400241231136011 |
oct | 706043346144233 |
9 | 132430377766532 |
10 | 31203400403099 |
11 | 9a40319069341 |
12 | 35bb5177b150b |
13 | 14546113613a2 |
14 | 79c3773488b1 |
15 | 391a1329b44e |
hex | 1c611b98c89b |
31203400403099 has 2 divisors, whose sum is σ = 31203400403100. Its totient is φ = 31203400403098.
The previous prime is 31203400403039. The next prime is 31203400403141. The reversal of 31203400403099 is 99030400430213.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31203400403099 - 28 = 31203400402843 is a prime.
It is a super-3 number, since 3×312034004030993 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (31203400403009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15601700201549 + 15601700201550.
It is an arithmetic number, because the mean of its divisors is an integer number (15601700201550).
Almost surely, 231203400403099 is an apocalyptic number.
31203400403099 is a deficient number, since it is larger than the sum of its proper divisors (1).
31203400403099 is an equidigital number, since it uses as much as digits as its factorization.
31203400403099 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 69984, while the sum is 38.
The spelling of 31203400403099 in words is "thirty-one trillion, two hundred three billion, four hundred million, four hundred three thousand, ninety-nine".
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