Base | Representation |
---|---|
bin | 11101000011111010… |
… | …011000010011110111 |
3 | 2222112200002222112122 |
4 | 131003322120103313 |
5 | 1002401230222341 |
6 | 22200205110155 |
7 | 2153160612536 |
oct | 350372302367 |
9 | 88480088478 |
10 | 31204148471 |
11 | 12262a23661 |
12 | 606a25835b |
13 | 2c339ac8a2 |
14 | 172033831d |
15 | c296d394b |
hex | 743e984f7 |
31204148471 has 2 divisors, whose sum is σ = 31204148472. Its totient is φ = 31204148470.
The previous prime is 31204148429. The next prime is 31204148473. The reversal of 31204148471 is 17484140213.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31204148471 - 26 = 31204148407 is a prime.
It is a super-3 number, since 3×312041484713 (a number of 32 digits) contains 333 as substring.
It is a Sophie Germain prime.
Together with 31204148473, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31204148473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15602074235 + 15602074236.
It is an arithmetic number, because the mean of its divisors is an integer number (15602074236).
Almost surely, 231204148471 is an apocalyptic number.
31204148471 is a deficient number, since it is larger than the sum of its proper divisors (1).
31204148471 is an equidigital number, since it uses as much as digits as its factorization.
31204148471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21504, while the sum is 35.
Adding to 31204148471 its reverse (17484140213), we get a palindrome (48688288684).
The spelling of 31204148471 in words is "thirty-one billion, two hundred four million, one hundred forty-eight thousand, four hundred seventy-one".
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