Base | Representation |
---|---|
bin | 11101000011111011… |
… | …011000111011001101 |
3 | 2222112200121102120221 |
4 | 131003323120323031 |
5 | 1002401312210013 |
6 | 22200214511341 |
7 | 2153163064255 |
oct | 350373307315 |
9 | 88480542527 |
10 | 31204413133 |
11 | 12263094493 |
12 | 606a365551 |
13 | 2c33a731aa |
14 | 17203a6965 |
15 | c2973708d |
hex | 743ed8ecd |
31204413133 has 2 divisors, whose sum is σ = 31204413134. Its totient is φ = 31204413132.
The previous prime is 31204413067. The next prime is 31204413151. The reversal of 31204413133 is 33131440213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30808323529 + 396089604 = 175523^2 + 19902^2 .
It is a cyclic number.
It is not a de Polignac number, because 31204413133 - 221 = 31202315981 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31204413098 and 31204413107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31204413173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15602206566 + 15602206567.
It is an arithmetic number, because the mean of its divisors is an integer number (15602206567).
Almost surely, 231204413133 is an apocalyptic number.
It is an amenable number.
31204413133 is a deficient number, since it is larger than the sum of its proper divisors (1).
31204413133 is an equidigital number, since it uses as much as digits as its factorization.
31204413133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 31204413133 its reverse (33131440213), we get a palindrome (64335853346).
The spelling of 31204413133 in words is "thirty-one billion, two hundred four million, four hundred thirteen thousand, one hundred thirty-three".
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