Base | Representation |
---|---|
bin | 101101011010101010000… |
… | …110001010101001110010 |
3 | 102001100211212010011012211 |
4 | 231122222012022221302 |
5 | 402113302000000424 |
6 | 10345433445242334 |
7 | 441325201200523 |
oct | 55325206125162 |
9 | 12040755104184 |
10 | 3121000000114 |
11 | aa3677154777 |
12 | 424a547033aa |
13 | 198402c544c9 |
14 | ab0b2d8a84a |
15 | 562b73cab94 |
hex | 2d6aa18aa72 |
3121000000114 has 16 divisors (see below), whose sum is σ = 4705251364800. Its totient is φ = 1552583633040.
The previous prime is 3121000000109. The next prime is 3121000000147. The reversal of 3121000000114 is 4110000001213.
It is a junction number, because it is equal to n+sod(n) for n = 3121000000094 and 3121000000103.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8614732 + ... + 8969704.
It is an arithmetic number, because the mean of its divisors is an integer number (294078210300).
Almost surely, 23121000000114 is an apocalyptic number.
3121000000114 is a deficient number, since it is larger than the sum of its proper divisors (1584251364686).
3121000000114 is a wasteful number, since it uses less digits than its factorization.
3121000000114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 377265.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 3121000000114 its reverse (4110000001213), we get a palindrome (7231000001327).
The spelling of 3121000000114 in words is "three trillion, one hundred twenty-one billion, one hundred fourteen", and thus it is an aban number.
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