Base | Representation |
---|---|
bin | 1110001100010101110000… |
… | …01110010011111001101101 |
3 | 11002111200022002012022101021 |
4 | 13012022320032103321231 |
5 | 13042322220210211023 |
6 | 150213454032214141 |
7 | 6400604621306104 |
oct | 706127016237155 |
9 | 132450262168337 |
10 | 31210323132013 |
11 | 9a43250836003 |
12 | 360092a09a351 |
13 | 145517565109c |
14 | 79c83290d03b |
15 | 391cbae0035d |
hex | 1c62b8393e6d |
31210323132013 has 2 divisors, whose sum is σ = 31210323132014. Its totient is φ = 31210323132012.
The previous prime is 31210323131947. The next prime is 31210323132047. The reversal of 31210323132013 is 31023132301213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 29297559449284 + 1912763682729 = 5412722^2 + 1383027^2 .
It is a cyclic number.
It is not a de Polignac number, because 31210323132013 - 237 = 31072884178541 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31210323132113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15605161566006 + 15605161566007.
It is an arithmetic number, because the mean of its divisors is an integer number (15605161566007).
Almost surely, 231210323132013 is an apocalyptic number.
It is an amenable number.
31210323132013 is a deficient number, since it is larger than the sum of its proper divisors (1).
31210323132013 is an equidigital number, since it uses as much as digits as its factorization.
31210323132013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 31210323132013 its reverse (31023132301213), we get a palindrome (62233455433226).
The spelling of 31210323132013 in words is "thirty-one trillion, two hundred ten billion, three hundred twenty-three million, one hundred thirty-two thousand, thirteen".
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