Base | Representation |
---|---|
bin | 100011011110111001100100… |
… | …0000100001101000110100101 |
3 | 1111221002102120022201110000221 |
4 | 1012331303020010031012211 |
5 | 311402102330220324143 |
6 | 3023445212321404341 |
7 | 122512130514245515 |
oct | 10675631004150645 |
9 | 1457072508643027 |
10 | 312110040011173 |
11 | 904a2140992418 |
12 | 2b009024a996b1 |
13 | 1051cb09690241 |
14 | 57102c6a51845 |
15 | 2613a7212c2ed |
hex | 11bdcc810d1a5 |
312110040011173 has 2 divisors, whose sum is σ = 312110040011174. Its totient is φ = 312110040011172.
The previous prime is 312110040011153. The next prime is 312110040011197. The reversal of 312110040011173 is 371110040011213.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 156300554088484 + 155809485922689 = 12502022^2 + 12482367^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-312110040011173 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312110040011123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156055020005586 + 156055020005587.
It is an arithmetic number, because the mean of its divisors is an integer number (156055020005587).
Almost surely, 2312110040011173 is an apocalyptic number.
It is an amenable number.
312110040011173 is a deficient number, since it is larger than the sum of its proper divisors (1).
312110040011173 is an equidigital number, since it uses as much as digits as its factorization.
312110040011173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 25.
Adding to 312110040011173 its reverse (371110040011213), we get a palindrome (683220080022386).
The spelling of 312110040011173 in words is "three hundred twelve trillion, one hundred ten billion, forty million, eleven thousand, one hundred seventy-three".
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