Base | Representation |
---|---|
bin | 11101000100010100… |
… | …101000101100000100 |
3 | 2222120011001200000020 |
4 | 131010110220230010 |
5 | 1002410011000200 |
6 | 22201012415140 |
7 | 2153303250231 |
oct | 350424505404 |
9 | 88504050006 |
10 | 31211031300 |
11 | 122668a4849 |
12 | 60706174b0 |
13 | 2c3524c677 |
14 | 172120a788 |
15 | c2a0e2ea0 |
hex | 744528b04 |
31211031300 has 72 divisors (see below), whose sum is σ = 90462564192. Its totient is φ = 8308320000.
The previous prime is 31211031281. The next prime is 31211031337. The reversal of 31211031300 is 313011213.
It is a super-3 number, since 3×312110313003 (a number of 32 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 31211031300.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 80200 + ... + 262400.
Almost surely, 231211031300 is an apocalyptic number.
31211031300 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 31211031300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (45231282096).
31211031300 is an abundant number, since it is smaller than the sum of its proper divisors (59251532892).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31211031300 is a wasteful number, since it uses less digits than its factorization.
31211031300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 182789 (or 182782 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 31211031300 its reverse (313011213), we get a palindrome (31524042513).
The spelling of 31211031300 in words is "thirty-one billion, two hundred eleven million, thirty-one thousand, three hundred".
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