Base | Representation |
---|---|
bin | 11101000100010101… |
… | …010100100111010111 |
3 | 2222120011101210211001 |
4 | 131010111110213113 |
5 | 1002410032224343 |
6 | 22201020324131 |
7 | 2153304626623 |
oct | 350425244727 |
9 | 88504353731 |
10 | 31211211223 |
11 | 12266a07a45 |
12 | 60706a3647 |
13 | 2c352b352a |
14 | 1721256183 |
15 | c2a12b44d |
hex | 7445549d7 |
31211211223 has 2 divisors, whose sum is σ = 31211211224. Its totient is φ = 31211211222.
The previous prime is 31211211221. The next prime is 31211211257. The reversal of 31211211223 is 32211211213.
It is a weak prime.
It is an emirp because it is prime and its reverse (32211211213) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31211211223 - 21 = 31211211221 is a prime.
Together with 31211211221, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 31211211223.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31211211221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15605605611 + 15605605612.
It is an arithmetic number, because the mean of its divisors is an integer number (15605605612).
Almost surely, 231211211223 is an apocalyptic number.
31211211223 is a deficient number, since it is larger than the sum of its proper divisors (1).
31211211223 is an equidigital number, since it uses as much as digits as its factorization.
31211211223 is an evil number, because the sum of its binary digits is even.
The product of its digits is 144, while the sum is 19.
Adding to 31211211223 its reverse (32211211213), we get a palindrome (63422422436).
The spelling of 31211211223 in words is "thirty-one billion, two hundred eleven million, two hundred eleven thousand, two hundred twenty-three".
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