Base | Representation |
---|---|
bin | 1110001100010111100110… |
… | …01110110010100011011111 |
3 | 11002111202212002000120102021 |
4 | 13012023303032302203133 |
5 | 13042331232124111221 |
6 | 150214140155041011 |
7 | 6400641302102002 |
oct | 706136316624337 |
9 | 132452762016367 |
10 | 31211313113311 |
11 | 9a43709636671 |
12 | 3600b65740167 |
13 | 14552a2791036 |
14 | 79c8c81ad539 |
15 | 391d27ca3041 |
hex | 1c62f33b28df |
31211313113311 has 2 divisors, whose sum is σ = 31211313113312. Its totient is φ = 31211313113310.
The previous prime is 31211313113293. The next prime is 31211313113411. The reversal of 31211313113311 is 11331131311213.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31211313113311 - 215 = 31211313080543 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31211313113411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15605656556655 + 15605656556656.
It is an arithmetic number, because the mean of its divisors is an integer number (15605656556656).
Almost surely, 231211313113311 is an apocalyptic number.
31211313113311 is a deficient number, since it is larger than the sum of its proper divisors (1).
31211313113311 is an equidigital number, since it uses as much as digits as its factorization.
31211313113311 is an evil number, because the sum of its binary digits is even.
The product of its digits is 486, while the sum is 25.
Adding to 31211313113311 its reverse (11331131311213), we get a palindrome (42542444424524).
The spelling of 31211313113311 in words is "thirty-one trillion, two hundred eleven billion, three hundred thirteen million, one hundred thirteen thousand, three hundred eleven".
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