Base | Representation |
---|---|
bin | 101101011010110010101… |
… | …100101111011110001111 |
3 | 102001101012220200212202212 |
4 | 231122302230233132033 |
5 | 402114100422031002 |
6 | 10345500042541035 |
7 | 441331603033655 |
oct | 55326254573617 |
9 | 12041186625685 |
10 | 3121144330127 |
11 | aa3740673a7a |
12 | 424a94b0777b |
13 | 198426b19695 |
14 | ab0c81dadd5 |
15 | 562c4dda352 |
hex | 2d6b2b2f78f |
3121144330127 has 2 divisors, whose sum is σ = 3121144330128. Its totient is φ = 3121144330126.
The previous prime is 3121144330027. The next prime is 3121144330163. The reversal of 3121144330127 is 7210334411213.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3121144330127 - 214 = 3121144313743 is a prime.
It is a super-2 number, since 2×31211443301272 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3121144330093 and 3121144330102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3121144330027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560572165063 + 1560572165064.
It is an arithmetic number, because the mean of its divisors is an integer number (1560572165064).
Almost surely, 23121144330127 is an apocalyptic number.
3121144330127 is a deficient number, since it is larger than the sum of its proper divisors (1).
3121144330127 is an equidigital number, since it uses as much as digits as its factorization.
3121144330127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 32.
The spelling of 3121144330127 in words is "three trillion, one hundred twenty-one billion, one hundred forty-four million, three hundred thirty thousand, one hundred twenty-seven".
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