Base | Representation |
---|---|
bin | 1110001100011001000110… |
… | …11101101011100101101011 |
3 | 11002111211221110200200211212 |
4 | 13012030203131223211223 |
5 | 13042334411303321212 |
6 | 150214352343143335 |
7 | 6401000326214552 |
oct | 706144335534553 |
9 | 132454843620755 |
10 | 31212122323307 |
11 | 9a43a94398062 |
12 | 3601150744b4b |
13 | 14553a131a013 |
14 | 79c963854d99 |
15 | 391d73d48e22 |
hex | 1c632376b96b |
31212122323307 has 2 divisors, whose sum is σ = 31212122323308. Its totient is φ = 31212122323306.
The previous prime is 31212122323303. The next prime is 31212122323309. The reversal of 31212122323307 is 70332322121213.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31212122323307 - 22 = 31212122323303 is a prime.
Together with 31212122323309, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (31212122323303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15606061161653 + 15606061161654.
It is an arithmetic number, because the mean of its divisors is an integer number (15606061161654).
Almost surely, 231212122323307 is an apocalyptic number.
31212122323307 is a deficient number, since it is larger than the sum of its proper divisors (1).
31212122323307 is an equidigital number, since it uses as much as digits as its factorization.
31212122323307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18144, while the sum is 32.
The spelling of 31212122323307 in words is "thirty-one trillion, two hundred twelve billion, one hundred twenty-two million, three hundred twenty-three thousand, three hundred seven".
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