Base | Representation |
---|---|
bin | 100011011111000011010111… |
… | …1010110000100101010110011 |
3 | 1111221011102221000222212112221 |
4 | 1012332012233112010222303 |
5 | 311402423443111220144 |
6 | 3023503014200301511 |
7 | 122513504431124263 |
oct | 10676065726045263 |
9 | 1457142830885487 |
10 | 312131100101299 |
11 | 90500068847886 |
12 | 2b011121a71897 |
13 | 10521ab488402b |
14 | 5711323a477a3 |
15 | 26143a5e98d84 |
hex | 11be1af584ab3 |
312131100101299 has 2 divisors, whose sum is σ = 312131100101300. Its totient is φ = 312131100101298.
The previous prime is 312131100101263. The next prime is 312131100101333. The reversal of 312131100101299 is 992101001131213.
It is an a-pointer prime, because the next prime (312131100101333) can be obtained adding 312131100101299 to its sum of digits (34).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 312131100101299 - 247 = 171393611745971 is a prime.
It is a super-2 number, since 2×3121311001012992 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (312131100101699) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156065550050649 + 156065550050650.
It is an arithmetic number, because the mean of its divisors is an integer number (156065550050650).
Almost surely, 2312131100101299 is an apocalyptic number.
312131100101299 is a deficient number, since it is larger than the sum of its proper divisors (1).
312131100101299 is an equidigital number, since it uses as much as digits as its factorization.
312131100101299 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2916, while the sum is 34.
The spelling of 312131100101299 in words is "three hundred twelve trillion, one hundred thirty-one billion, one hundred million, one hundred one thousand, two hundred ninety-nine".
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