Base | Representation |
---|---|
bin | 1110001100011011001000… |
… | …10111100010001110100111 |
3 | 11002111221202100122221120201 |
4 | 13012031210113202032213 |
5 | 13042344124033344033 |
6 | 150215052402211331 |
7 | 6401036320612144 |
oct | 706154427421647 |
9 | 132457670587521 |
10 | 31213211231143 |
11 | 9a444a3016697 |
12 | 36013b5353b47 |
13 | 1455515ab5c96 |
14 | 79ca283073cb |
15 | 391dd973d47d |
hex | 1c63645e23a7 |
31213211231143 has 2 divisors, whose sum is σ = 31213211231144. Its totient is φ = 31213211231142.
The previous prime is 31213211231101. The next prime is 31213211231287. The reversal of 31213211231143 is 34113211231213.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31213211231143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31213211831143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15606605615571 + 15606605615572.
It is an arithmetic number, because the mean of its divisors is an integer number (15606605615572).
Almost surely, 231213211231143 is an apocalyptic number.
31213211231143 is a deficient number, since it is larger than the sum of its proper divisors (1).
31213211231143 is an equidigital number, since it uses as much as digits as its factorization.
31213211231143 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2592, while the sum is 28.
Adding to 31213211231143 its reverse (34113211231213), we get a palindrome (65326422462356).
The spelling of 31213211231143 in words is "thirty-one trillion, two hundred thirteen billion, two hundred eleven million, two hundred thirty-one thousand, one hundred forty-three".
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