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3121330210133 is a prime number
BaseRepresentation
bin101101011010111101110…
…001110100010101010101
3102001101200212110120012112
4231122331301310111111
5402114441013211013
610345530323000405
7441336321012122
oct55327561642525
912041625416175
103121330210133
11aa3826592413
12424b27209105
1319845649ba55
14ab104b85749
15562d63a5ba8
hex2d6bdc74555

3121330210133 has 2 divisors, whose sum is σ = 3121330210134. Its totient is φ = 3121330210132.

The previous prime is 3121330210109. The next prime is 3121330210147. The reversal of 3121330210133 is 3310120331213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3013498099249 + 107832110884 = 1735943^2 + 328378^2 .

It is a cyclic number.

It is not a de Polignac number, because 3121330210133 - 214 = 3121330193749 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3121330210099 and 3121330210108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3121330216133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560665105066 + 1560665105067.

It is an arithmetic number, because the mean of its divisors is an integer number (1560665105067).

Almost surely, 23121330210133 is an apocalyptic number.

It is an amenable number.

3121330210133 is a deficient number, since it is larger than the sum of its proper divisors (1).

3121330210133 is an equidigital number, since it uses as much as digits as its factorization.

3121330210133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 3121330210133 its reverse (3310120331213), we get a palindrome (6431450541346).

The spelling of 3121330210133 in words is "three trillion, one hundred twenty-one billion, three hundred thirty million, two hundred ten thousand, one hundred thirty-three".