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31213614141421 is a prime number
BaseRepresentation
bin1110001100011011111000…
…11000100000111111101101
311002111222210102210220120121
413012031330120200333231
513042400440210011141
6150215200354044541
76401052312364525
oct706157430407755
9132458712726517
1031213614141421
119a4468a49a098
1236014a8279751
13145557b40612a
1479ca65a28685
15391e0ecc91d1
hex1c637c620fed

31213614141421 has 2 divisors, whose sum is σ = 31213614141422. Its totient is φ = 31213614141420.

The previous prime is 31213614141403. The next prime is 31213614141473. The reversal of 31213614141421 is 12414141631213.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 27127576395396 + 4086037746025 = 5208414^2 + 2021395^2 .

It is a cyclic number.

It is not a de Polignac number, because 31213614141421 - 25 = 31213614141389 is a prime.

It is a super-3 number, since 3×312136141414213 (a number of 41 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31213614141401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15606807070710 + 15606807070711.

It is an arithmetic number, because the mean of its divisors is an integer number (15606807070711).

Almost surely, 231213614141421 is an apocalyptic number.

It is an amenable number.

31213614141421 is a deficient number, since it is larger than the sum of its proper divisors (1).

31213614141421 is an equidigital number, since it uses as much as digits as its factorization.

31213614141421 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 13824, while the sum is 34.

Adding to 31213614141421 its reverse (12414141631213), we get a palindrome (43627755772634).

The spelling of 31213614141421 in words is "thirty-one trillion, two hundred thirteen billion, six hundred fourteen million, one hundred forty-one thousand, four hundred twenty-one".