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312141404404397 is a prime number
BaseRepresentation
bin100011011111001000001010…
…1100001110111101010101101
31111221012102112011100201001102
41012332100111201313222231
5311403111044011420042
63023511440453252445
7122514320662220261
oct10676202541675255
91457172464321042
10312141404404397
1190504476305257
122b013118934125
1310522a67617ab9
145711a203800a1
1526147aa915b32
hex11be415877aad

312141404404397 has 2 divisors, whose sum is σ = 312141404404398. Its totient is φ = 312141404404396.

The previous prime is 312141404404391. The next prime is 312141404404457. The reversal of 312141404404397 is 793404404141213.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 311976128819716 + 165275584681 = 17662846^2 + 406541^2 .

It is a cyclic number.

It is not a de Polignac number, because 312141404404397 - 24 = 312141404404381 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (312141404404391) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156070702202198 + 156070702202199.

It is an arithmetic number, because the mean of its divisors is an integer number (156070702202199).

Almost surely, 2312141404404397 is an apocalyptic number.

It is an amenable number.

312141404404397 is a deficient number, since it is larger than the sum of its proper divisors (1).

312141404404397 is an equidigital number, since it uses as much as digits as its factorization.

312141404404397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1161216, while the sum is 47.

The spelling of 312141404404397 in words is "three hundred twelve trillion, one hundred forty-one billion, four hundred four million, four hundred four thousand, three hundred ninety-seven".