Base | Representation |
---|---|
bin | 1110001100011101000010… |
… | …00110010011010111110111 |
3 | 11002112001101100220001212001 |
4 | 13012032201012103113313 |
5 | 13042403220402432043 |
6 | 150215341440440131 |
7 | 6401103502221262 |
oct | 706164106232767 |
9 | 132461340801761 |
10 | 31214230124023 |
11 | 9a44976173a21 |
12 | 360163a619047 |
13 | 1455648c0968b |
14 | 79cac3771cd9 |
15 | 391e48e0274d |
hex | 1c63a11935f7 |
31214230124023 has 2 divisors, whose sum is σ = 31214230124024. Its totient is φ = 31214230124022.
The previous prime is 31214230123891. The next prime is 31214230124149. The reversal of 31214230124023 is 32042103241213.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31214230124023 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31214230123982 and 31214230124000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31214230124423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15607115062011 + 15607115062012.
It is an arithmetic number, because the mean of its divisors is an integer number (15607115062012).
Almost surely, 231214230124023 is an apocalyptic number.
31214230124023 is a deficient number, since it is larger than the sum of its proper divisors (1).
31214230124023 is an equidigital number, since it uses as much as digits as its factorization.
31214230124023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 31214230124023 its reverse (32042103241213), we get a palindrome (63256333365236).
The spelling of 31214230124023 in words is "thirty-one trillion, two hundred fourteen billion, two hundred thirty million, one hundred twenty-four thousand, twenty-three".
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