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31214230124149 is a prime number
BaseRepresentation
bin1110001100011101000010…
…00110010011011001110101
311002112001101100220002000201
413012032201012103121311
513042403220402433044
6150215341440440501
76401103502221532
oct706164106233165
9132461340802021
1031214230124149
119a44976174026
12360163a619131
131455648c09757
1479cac3771d89
15391e48e027d4
hex1c63a1193675

31214230124149 has 2 divisors, whose sum is σ = 31214230124150. Its totient is φ = 31214230124148.

The previous prime is 31214230124023. The next prime is 31214230124173. The reversal of 31214230124149 is 94142103241213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20112372641124 + 11101857483025 = 4484682^2 + 3331945^2 .

It is a cyclic number.

It is not a de Polignac number, because 31214230124149 - 215 = 31214230091381 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31214230125149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15607115062074 + 15607115062075.

It is an arithmetic number, because the mean of its divisors is an integer number (15607115062075).

Almost surely, 231214230124149 is an apocalyptic number.

It is an amenable number.

31214230124149 is a deficient number, since it is larger than the sum of its proper divisors (1).

31214230124149 is an equidigital number, since it uses as much as digits as its factorization.

31214230124149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41472, while the sum is 37.

The spelling of 31214230124149 in words is "thirty-one trillion, two hundred fourteen billion, two hundred thirty million, one hundred twenty-four thousand, one hundred forty-nine".