Base | Representation |
---|---|
bin | 1001000101100001010… |
… | …00110110010000101101 |
3 | 1002211211211112022212221 |
4 | 10202300220312100231 |
5 | 20103341443041331 |
6 | 355231225555341 |
7 | 31361430634663 |
oct | 4426050662055 |
9 | 1084754468787 |
10 | 312201143341 |
11 | 11044945193a |
12 | 5060b645b51 |
13 | 2359585ac59 |
14 | 1117975cc33 |
15 | 81c3912711 |
hex | 48b0a3642d |
312201143341 has 2 divisors, whose sum is σ = 312201143342. Its totient is φ = 312201143340.
The previous prime is 312201143327. The next prime is 312201143347. The reversal of 312201143341 is 143341102213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 300144005316 + 12057138025 = 547854^2 + 109805^2 .
It is a cyclic number.
It is not a de Polignac number, because 312201143341 - 211 = 312201141293 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312201143347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156100571670 + 156100571671.
It is an arithmetic number, because the mean of its divisors is an integer number (156100571671).
Almost surely, 2312201143341 is an apocalyptic number.
It is an amenable number.
312201143341 is a deficient number, since it is larger than the sum of its proper divisors (1).
312201143341 is an equidigital number, since it uses as much as digits as its factorization.
312201143341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 312201143341 its reverse (143341102213), we get a palindrome (455542245554).
The spelling of 312201143341 in words is "three hundred twelve billion, two hundred one million, one hundred forty-three thousand, three hundred forty-one".
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