Base | Representation |
---|---|
bin | 1001000101100010010… |
… | …11111001110111001011 |
3 | 1002211212110211012220112 |
4 | 10202301023321313023 |
5 | 20103401321130011 |
6 | 355232154544535 |
7 | 31361602021244 |
oct | 4426113716713 |
9 | 1084773735815 |
10 | 312210333131 |
11 | 110453659304 |
12 | 5061273814b |
13 | 23597727ab8 |
14 | 1117aa71ccb |
15 | 81c462a58b |
hex | 48b12f9dcb |
312210333131 has 2 divisors, whose sum is σ = 312210333132. Its totient is φ = 312210333130.
The previous prime is 312210333089. The next prime is 312210333133. The reversal of 312210333131 is 131333012213.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 312210333131 - 234 = 295030463947 is a prime.
It is a super-2 number, since 2×3122103331312 (a number of 24 digits) contains 22 as substring.
Together with 312210333133, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 312210333097 and 312210333106.
It is not a weakly prime, because it can be changed into another prime (312210333133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156105166565 + 156105166566.
It is an arithmetic number, because the mean of its divisors is an integer number (156105166566).
Almost surely, 2312210333131 is an apocalyptic number.
312210333131 is a deficient number, since it is larger than the sum of its proper divisors (1).
312210333131 is an equidigital number, since it uses as much as digits as its factorization.
312210333131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 312210333131 its reverse (131333012213), we get a palindrome (443543345344).
The spelling of 312210333131 in words is "three hundred twelve billion, two hundred ten million, three hundred thirty-three thousand, one hundred thirty-one".
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