Base | Representation |
---|---|
bin | 11101000100111100… |
… | …010100011100011111 |
3 | 2222120212122012000201 |
4 | 131010330110130133 |
5 | 1002420141343033 |
6 | 22202023404331 |
7 | 2153460545224 |
oct | 350474243437 |
9 | 88525565021 |
10 | 31221434143 |
11 | 1227175a639 |
12 | 6073bb36a7 |
13 | 2c374526b3 |
14 | 172275794b |
15 | c2ae9a47d |
hex | 744f1471f |
31221434143 has 2 divisors, whose sum is σ = 31221434144. Its totient is φ = 31221434142.
The previous prime is 31221434119. The next prime is 31221434149. The reversal of 31221434143 is 34143412213.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31221434143 - 221 = 31219336991 is a prime.
It is a super-3 number, since 3×312214341433 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31221434149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15610717071 + 15610717072.
It is an arithmetic number, because the mean of its divisors is an integer number (15610717072).
Almost surely, 231221434143 is an apocalyptic number.
31221434143 is a deficient number, since it is larger than the sum of its proper divisors (1).
31221434143 is an equidigital number, since it uses as much as digits as its factorization.
31221434143 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6912, while the sum is 28.
Adding to 31221434143 its reverse (34143412213), we get a palindrome (65364846356).
The spelling of 31221434143 in words is "thirty-one billion, two hundred twenty-one million, four hundred thirty-four thousand, one hundred forty-three".
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