Base | Representation |
---|---|
bin | 1110001100111011001001… |
… | …00000010000111111111011 |
3 | 11002120121002210221000011112 |
4 | 13012131210200100333323 |
5 | 13043134321201422201 |
6 | 150231013351350535 |
7 | 6402215155550033 |
oct | 706354440207773 |
9 | 132517083830145 |
10 | 31230393389051 |
11 | 9a5080a99119a |
12 | 36047ab68244b |
13 | 145702375751c |
14 | 79d7b82828c3 |
15 | 392592de80bb |
hex | 1c6764810ffb |
31230393389051 has 2 divisors, whose sum is σ = 31230393389052. Its totient is φ = 31230393389050.
The previous prime is 31230393389023. The next prime is 31230393389053. The reversal of 31230393389051 is 15098339303213.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (15098339303213) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31230393389051 - 226 = 31230326280187 is a prime.
Together with 31230393389053, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (31230393389053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15615196694525 + 15615196694526.
It is an arithmetic number, because the mean of its divisors is an integer number (15615196694526).
Almost surely, 231230393389051 is an apocalyptic number.
31230393389051 is a deficient number, since it is larger than the sum of its proper divisors (1).
31230393389051 is an equidigital number, since it uses as much as digits as its factorization.
31230393389051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1574640, while the sum is 50.
The spelling of 31230393389051 in words is "thirty-one trillion, two hundred thirty billion, three hundred ninety-three million, three hundred eighty-nine thousand, fifty-one".
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