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31231120313131 is a prime number
BaseRepresentation
bin1110001100111100011111…
…10101010000101100101011
311002120122222110202120112121
413012132033311100230223
513043142313300010011
6150231213440052111
76402242163366154
oct706361765205453
9132518873676477
1031231120313131
119a5105324aaa2
123604973004037
13145710b23280b
1479d846a2892b
153925d6b37e71
hex1c678fd50b2b

31231120313131 has 2 divisors, whose sum is σ = 31231120313132. Its totient is φ = 31231120313130.

The previous prime is 31231120313111. The next prime is 31231120313137. The reversal of 31231120313131 is 13131302113213.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 31231120313131 - 225 = 31231086758699 is a prime.

It is a super-3 number, since 3×312311203131313 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 31231120313096 and 31231120313105.

It is not a weakly prime, because it can be changed into another prime (31231120313137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15615560156565 + 15615560156566.

It is an arithmetic number, because the mean of its divisors is an integer number (15615560156566).

Almost surely, 231231120313131 is an apocalyptic number.

31231120313131 is a deficient number, since it is larger than the sum of its proper divisors (1).

31231120313131 is an equidigital number, since it uses as much as digits as its factorization.

31231120313131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 31231120313131 its reverse (13131302113213), we get a palindrome (44362422426344).

The spelling of 31231120313131 in words is "thirty-one trillion, two hundred thirty-one billion, one hundred twenty million, three hundred thirteen thousand, one hundred thirty-one".