Base | Representation |
---|---|
bin | 100011100000010111101001… |
… | …1110110100001010000011110 |
3 | 1111221210202010022112001011200 |
4 | 1013000233103312201100132 |
5 | 311413410140402310324 |
6 | 3024122110522300330 |
7 | 122532543004156104 |
oct | 10700572366412036 |
9 | 1457722108461150 |
10 | 312312101213214 |
11 | 9056a9001a2183 |
12 | 2b0402169576a6 |
13 | 10535b9ba3489b |
14 | 5719db479dc74 |
15 | 2618e4b502ec9 |
hex | 11c0bd3da141e |
312312101213214 has 24 divisors (see below), whose sum is σ = 677104766677560. Its totient is φ = 104038103371248.
The previous prime is 312312101213159. The next prime is 312312101213269. The reversal of 312312101213214 is 412312101213213.
312312101213214 is a `hidden beast` number, since 3 + 1 + 2 + 3 + 1 + 210 + 121 + 321 + 4 = 666.
It is an interprime number because it is at equal distance from previous prime (312312101213159) and next prime (312312101213269).
It is a super-3 number, since 3×3123121012132143 (a number of 44 digits) contains 333 as substring.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5494167997 + ... + 5494224840.
It is an arithmetic number, because the mean of its divisors is an integer number (28212698611565).
Almost surely, 2312312101213214 is an apocalyptic number.
312312101213214 is an abundant number, since it is smaller than the sum of its proper divisors (364792665464346).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
312312101213214 is a wasteful number, since it uses less digits than its factorization.
312312101213214 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10988394424 (or 10988394421 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 27.
Adding to 312312101213214 its reverse (412312101213213), we get a palindrome (724624202426427).
Subtracting 312312101213214 from its reverse (412312101213213), we obtain a palindrome (99999999999999).
The spelling of 312312101213214 in words is "three hundred twelve trillion, three hundred twelve billion, one hundred one million, two hundred thirteen thousand, two hundred fourteen".
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