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3123300312133 is a prime number
BaseRepresentation
bin101101011100110011001…
…101001010010001000101
3102001120210011120010002021
4231130303031022101011
5402133004334442013
610350454021043141
7441436202421541
oct55346315122105
912046704503067
103123300312133
11aa4647669191
12425396b564b1
131986ab6a8691
14ab25069aa21
155639e30ea8d
hex2d73334a445

3123300312133 has 2 divisors, whose sum is σ = 3123300312134. Its totient is φ = 3123300312132.

The previous prime is 3123300312079. The next prime is 3123300312137. The reversal of 3123300312133 is 3312130033213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2643817464324 + 479482847809 = 1625982^2 + 692447^2 .

It is a cyclic number.

It is not a de Polignac number, because 3123300312133 - 217 = 3123300181061 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3123300312098 and 3123300312107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3123300312137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1561650156066 + 1561650156067.

It is an arithmetic number, because the mean of its divisors is an integer number (1561650156067).

Almost surely, 23123300312133 is an apocalyptic number.

It is an amenable number.

3123300312133 is a deficient number, since it is larger than the sum of its proper divisors (1).

3123300312133 is an equidigital number, since it uses as much as digits as its factorization.

3123300312133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2916, while the sum is 25.

Adding to 3123300312133 its reverse (3312130033213), we get a palindrome (6435430345346).

The spelling of 3123300312133 in words is "three trillion, one hundred twenty-three billion, three hundred million, three hundred twelve thousand, one hundred thirty-three".