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31233014330249 is a prime number
BaseRepresentation
bin1110001101000000000001…
…01110010111001110001001
311002120211212110200121120202
413012200000232113032021
513043210203132031444
6150232125415301545
76402340132310024
oct706400056271611
9132524773617522
1031233014330249
119a5193538a0a6
12360520137a8b5
1314573507500c4
1479d9863b61bb
1539269806334e
hex1c6800b97389

31233014330249 has 2 divisors, whose sum is σ = 31233014330250. Its totient is φ = 31233014330248.

The previous prime is 31233014330201. The next prime is 31233014330251. The reversal of 31233014330249 is 94203341033213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16850261478649 + 14382752851600 = 4104907^2 + 3792460^2 .

It is a cyclic number.

It is not a de Polignac number, because 31233014330249 - 228 = 31232745894793 is a prime.

Together with 31233014330251, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (31233014330279) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15616507165124 + 15616507165125.

It is an arithmetic number, because the mean of its divisors is an integer number (15616507165125).

Almost surely, 231233014330249 is an apocalyptic number.

It is an amenable number.

31233014330249 is a deficient number, since it is larger than the sum of its proper divisors (1).

31233014330249 is an equidigital number, since it uses as much as digits as its factorization.

31233014330249 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 139968, while the sum is 38.

The spelling of 31233014330249 in words is "thirty-one trillion, two hundred thirty-three billion, fourteen million, three hundred thirty thousand, two hundred forty-nine".