Search a number
-
+
31233103117 is a prime number
BaseRepresentation
bin11101000101101000…
…110101010100001101
32222121200121000211221
4131011220311110031
51002431133244432
622203121443341
72153661665446
oct350550652415
988550530757
1031233103117
11122782aa717
126077aa0551
132c399a9b08
1417241142cd
15c2c002b97
hex745a3550d

31233103117 has 2 divisors, whose sum is σ = 31233103118. Its totient is φ = 31233103116.

The previous prime is 31233103081. The next prime is 31233103129. The reversal of 31233103117 is 71130133213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 25374578436 + 5858524681 = 159294^2 + 76541^2 .

It is an emirp because it is prime and its reverse (71130133213) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 31233103117 - 211 = 31233101069 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 31233103091 and 31233103100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31233103157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15616551558 + 15616551559.

It is an arithmetic number, because the mean of its divisors is an integer number (15616551559).

Almost surely, 231233103117 is an apocalyptic number.

It is an amenable number.

31233103117 is a deficient number, since it is larger than the sum of its proper divisors (1).

31233103117 is an equidigital number, since it uses as much as digits as its factorization.

31233103117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1134, while the sum is 25.

The spelling of 31233103117 in words is "thirty-one billion, two hundred thirty-three million, one hundred three thousand, one hundred seventeen".