Base | Representation |
---|---|
bin | 101101011100110100011… |
… | …110001010000101011010 |
3 | 102001120211122111212011121 |
4 | 231130310132022011122 |
5 | 402133030303420200 |
6 | 10350500100115454 |
7 | 441436551044230 |
oct | 55346436120532 |
9 | 12046748455147 |
10 | 3123321545050 |
11 | aa4658650853 |
12 | 4253a2095b8a |
13 | 1986b2c01035 |
14 | ab253426950 |
15 | 563a1105e1a |
hex | 2d73478a15a |
3123321545050 has 48 divisors (see below), whose sum is σ = 6660637656192. Its totient is φ = 1067409806400.
The previous prime is 3123321545033. The next prime is 3123321545077. The reversal of 3123321545050 is 505451233213.
3123321545050 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 3123321544997 and 3123321545015.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 14238057 + ... + 14455756.
It is an arithmetic number, because the mean of its divisors is an integer number (138763284504).
Almost surely, 23123321545050 is an apocalyptic number.
3123321545050 is an abundant number, since it is smaller than the sum of its proper divisors (3537316111142).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3123321545050 is a wasteful number, since it uses less digits than its factorization.
3123321545050 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28694143 (or 28694138 counting only the distinct ones).
The product of its (nonzero) digits is 54000, while the sum is 34.
Adding to 3123321545050 its reverse (505451233213), we get a palindrome (3628772778263).
The spelling of 3123321545050 in words is "three trillion, one hundred twenty-three billion, three hundred twenty-one million, five hundred forty-five thousand, fifty".
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