Base | Representation |
---|---|
bin | 11101000101101100… |
… | …110000010100010111 |
3 | 2222121202112021010221 |
4 | 131011230300110113 |
5 | 1002431414144343 |
6 | 22203155455211 |
7 | 2154003510031 |
oct | 350554602427 |
9 | 88552467127 |
10 | 31234131223 |
11 | 12278942099 |
12 | 60782b7507 |
13 | 2c39c79a69 |
14 | 1724300c51 |
15 | c2c1575ed |
hex | 745b30517 |
31234131223 has 2 divisors, whose sum is σ = 31234131224. Its totient is φ = 31234131222.
The previous prime is 31234131199. The next prime is 31234131281. The reversal of 31234131223 is 32213143213.
It is a weak prime.
It is an emirp because it is prime and its reverse (32213143213) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31234131223 - 213 = 31234123031 is a prime.
It is a super-3 number, since 3×312341312233 (a number of 32 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31234131023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15617065611 + 15617065612.
It is an arithmetic number, because the mean of its divisors is an integer number (15617065612).
Almost surely, 231234131223 is an apocalyptic number.
31234131223 is a deficient number, since it is larger than the sum of its proper divisors (1).
31234131223 is an equidigital number, since it uses as much as digits as its factorization.
31234131223 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2592, while the sum is 25.
Adding to 31234131223 its reverse (32213143213), we get a palindrome (63447274436).
The spelling of 31234131223 in words is "thirty-one billion, two hundred thirty-four million, one hundred thirty-one thousand, two hundred twenty-three".
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