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312344101410403 is a prime number
BaseRepresentation
bin100011100000100110100011…
…1001101100101011001100011
31111221220210201110112111021011
41013001031013031211121203
5311414421204430113103
63024144522125441351
7122535055002310456
oct10701150715453143
91457823643474234
10312344101410403
11905824314a7a37
122b046467710257
1310538bcb6129ca
14571b76c71549d
152619bc0a2cd6d
hex11c1347365663

312344101410403 has 2 divisors, whose sum is σ = 312344101410404. Its totient is φ = 312344101410402.

The previous prime is 312344101410401. The next prime is 312344101410433. The reversal of 312344101410403 is 304014101443213.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 312344101410403 - 21 = 312344101410401 is a prime.

It is a super-2 number, since 2×3123441014104032 (a number of 30 digits) contains 22 as substring.

Together with 312344101410401, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (312344101410401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156172050705201 + 156172050705202.

It is an arithmetic number, because the mean of its divisors is an integer number (156172050705202).

Almost surely, 2312344101410403 is an apocalyptic number.

312344101410403 is a deficient number, since it is larger than the sum of its proper divisors (1).

312344101410403 is an equidigital number, since it uses as much as digits as its factorization.

312344101410403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 312344101410403 its reverse (304014101443213), we get a palindrome (616358202853616).

The spelling of 312344101410403 in words is "three hundred twelve trillion, three hundred forty-four billion, one hundred one million, four hundred ten thousand, four hundred three".