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312344101410401 is a prime number
BaseRepresentation
bin100011100000100110100011…
…1001101100101011001100001
31111221220210201110112111021002
41013001031013031211121201
5311414421204430113101
63024144522125441345
7122535055002310454
oct10701150715453141
91457823643474232
10312344101410401
11905824314a7a35
122b046467710255
1310538bcb6129c8
14571b76c71549b
152619bc0a2cd6b
hex11c1347365661

312344101410401 has 2 divisors, whose sum is σ = 312344101410402. Its totient is φ = 312344101410400.

The previous prime is 312344101410379. The next prime is 312344101410403. The reversal of 312344101410401 is 104014101443213.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 299854938342400 + 12489163068001 = 17316320^2 + 3534001^2 .

It is a cyclic number.

It is not a de Polignac number, because 312344101410401 - 210 = 312344101409377 is a prime.

Together with 312344101410403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (312344101410403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156172050705200 + 156172050705201.

It is an arithmetic number, because the mean of its divisors is an integer number (156172050705201).

Almost surely, 2312344101410401 is an apocalyptic number.

It is an amenable number.

312344101410401 is a deficient number, since it is larger than the sum of its proper divisors (1).

312344101410401 is an equidigital number, since it uses as much as digits as its factorization.

312344101410401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 312344101410401 its reverse (104014101443213), we get a palindrome (416358202853614).

The spelling of 312344101410401 in words is "three hundred twelve trillion, three hundred forty-four billion, one hundred one million, four hundred ten thousand, four hundred one".