Base | Representation |
---|---|
bin | 100011100000100110100011… |
… | …1010100011111100010011111 |
3 | 1111221220210201120221111111101 |
4 | 1013001031013110133202133 |
5 | 311414421210411041112 |
6 | 3024144522232333531 |
7 | 122535055023562405 |
oct | 10701150724374237 |
9 | 1457823646844441 |
10 | 312344103221407 |
11 | 90582432524634 |
12 | 2b0464682442a7 |
13 | 10538bcbac80ca |
14 | 571b76ca67475 |
15 | 2619bc0c89757 |
hex | 11c134751f89f |
312344103221407 has 2 divisors, whose sum is σ = 312344103221408. Its totient is φ = 312344103221406.
The previous prime is 312344103221387. The next prime is 312344103221431. The reversal of 312344103221407 is 704122301443213.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (704122301443213) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 312344103221407 - 231 = 312341955737759 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312344103221207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156172051610703 + 156172051610704.
It is an arithmetic number, because the mean of its divisors is an integer number (156172051610704).
Almost surely, 2312344103221407 is an apocalyptic number.
312344103221407 is a deficient number, since it is larger than the sum of its proper divisors (1).
312344103221407 is an equidigital number, since it uses as much as digits as its factorization.
312344103221407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96768, while the sum is 37.
The spelling of 312344103221407 in words is "three hundred twelve trillion, three hundred forty-four billion, one hundred three million, two hundred twenty-one thousand, four hundred seven".
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