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31240043429599 is a prime number
BaseRepresentation
bin1110001101001101000111…
…01100001111111011011111
311002121112000100011212011201
413012212203230033323133
513043314102104221344
6150235251113300331
76403006253544034
oct706464354177337
9132545010155151
1031240043429599
119a549120a9514
1236066434046a7
131457c00aa40a4
147a0051b4938b
1539295a1c94d4
hex1c69a3b0fedf

31240043429599 has 2 divisors, whose sum is σ = 31240043429600. Its totient is φ = 31240043429598.

The previous prime is 31240043429597. The next prime is 31240043429633. The reversal of 31240043429599 is 99592434004213.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 31240043429599 - 21 = 31240043429597 is a prime.

It is a super-3 number, since 3×312400434295993 (a number of 41 digits) contains 333 as substring.

Together with 31240043429597, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31240043429597) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15620021714799 + 15620021714800.

It is an arithmetic number, because the mean of its divisors is an integer number (15620021714800).

Almost surely, 231240043429599 is an apocalyptic number.

31240043429599 is a deficient number, since it is larger than the sum of its proper divisors (1).

31240043429599 is an equidigital number, since it uses as much as digits as its factorization.

31240043429599 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8398080, while the sum is 55.

The spelling of 31240043429599 in words is "thirty-one trillion, two hundred forty billion, forty-three million, four hundred twenty-nine thousand, five hundred ninety-nine".