312413114014049 has 2 divisors, whose sum is σ = 312413114014050. Its totient is φ = 312413114014048.

The previous prime is 312413114013989. The next prime is 312413114014051. The reversal of 312413114014049 is 940410411314213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 193842466343824 + 118570647670225 = 13922732^2 + 10889015^2 .

It is a cyclic number.

It is not a de Polignac number, because 312413114014049 - 2²⁴ = 312413097236833 is a prime.

It is a super-3 number, since 3×312413114014049³ (a number of 44 digits) contains 333 as substring.

Together with 312413114014051, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (312413114014349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156206557007024 + 156206557007025.

It is an arithmetic number, because the mean of its divisors is an integer number (156206557007025).

Almost surely, 2^{312413114014049} is an apocalyptic number.

It is an amenable number.

312413114014049 is a deficient number, since it is larger than the sum of its proper divisors (1).

312413114014049 is an equidigital number, since it uses as much as digits as its factorization.

312413114014049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41472, while the sum is 38.

The spelling of 312413114014049 in words is "three hundred twelve trillion, four hundred thirteen billion, one hundred fourteen million, fourteen thousand, forty-nine".