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31241411 is a prime number
BaseRepresentation
bin111011100101…
…1010011000011
32011210020011022
41313023103003
530444211121
63033340055
7526355555
oct167132303
964706138
1031241411
11166a9153
12a56762b
13661b056
1442134d5
152b21aab
hex1dcb4c3

31241411 has 2 divisors, whose sum is σ = 31241412. Its totient is φ = 31241410.

The previous prime is 31241401. The next prime is 31241443. The reversal of 31241411 is 11414213.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 31241411 - 210 = 31240387 is a prime.

It is a super-2 number, since 2×312414112 = 1952051522541842, which contains 22 as substring.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 31241411.

It is not a weakly prime, because it can be changed into another prime (31241401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15620705 + 15620706.

It is an arithmetic number, because the mean of its divisors is an integer number (15620706).

Almost surely, 231241411 is an apocalyptic number.

31241411 is a deficient number, since it is larger than the sum of its proper divisors (1).

31241411 is an equidigital number, since it uses as much as digits as its factorization.

31241411 is an evil number, because the sum of its binary digits is even.

The product of its digits is 96, while the sum is 17.

The square root of 31241411 is about 5589.4016674417. The cubic root of 31241411 is about 314.9514025978.

Adding to 31241411 its reverse (11414213), we get a palindrome (42655624).

The spelling of 31241411 in words is "thirty-one million, two hundred forty-one thousand, four hundred eleven".