312433402411130 has 64 divisors (see below), whose sum is σ = 755083803333888. Its totient is φ = 89890928962560.

The previous prime is 312433402411129. The next prime is 312433402411159. The reversal of 312433402411130 is 31114204334213.

It is a super-2 number, since 2×312433402411130² (a number of 30 digits) contains 22 as substring.

It is a Curzon number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 15606054047 + ... + 15606074066.

It is an arithmetic number, because the mean of its divisors is an integer number (11798184427092).

Almost surely, 2^{312433402411130} is an apocalyptic number.

312433402411130 is an abundant number, since it is smaller than the sum of its proper divisors (442650400922758).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

312433402411130 is a wasteful number, since it uses less digits than its factorization.

312433402411130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31212128151.

The product of its (nonzero) digits is 20736, while the sum is 32.

Adding to 312433402411130 its reverse (31114204334213), we get a palindrome (343547606745343).

The spelling of 312433402411130 in words is "three hundred twelve trillion, four hundred thirty-three billion, four hundred two million, four hundred eleven thousand, one hundred thirty".