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313005532425149 is a prime number
BaseRepresentation
bin100011100101011010100011…
…1100100101010101110111101
31112001021000222201200102200202
41013022311013210222232331
5312011240312300101044
63025412431223533245
7122633621612212034
oct10712650744525675
91461230881612622
10313005532425149
11908079a0020103
122b13269b5ba225
13105863ab317985
14574179751571b
15262bed3a6cc4e
hex11cad4792abbd

313005532425149 has 2 divisors, whose sum is σ = 313005532425150. Its totient is φ = 313005532425148.

The previous prime is 313005532425137. The next prime is 313005532425227. The reversal of 313005532425149 is 941524235500313.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 200619179280100 + 112386353145049 = 14164010^2 + 10601243^2 .

It is a cyclic number.

It is not a de Polignac number, because 313005532425149 - 24 = 313005532425133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (313005532425109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156502766212574 + 156502766212575.

It is an arithmetic number, because the mean of its divisors is an integer number (156502766212575).

Almost surely, 2313005532425149 is an apocalyptic number.

It is an amenable number.

313005532425149 is a deficient number, since it is larger than the sum of its proper divisors (1).

313005532425149 is an equidigital number, since it uses as much as digits as its factorization.

313005532425149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944000, while the sum is 47.

The spelling of 313005532425149 in words is "three hundred thirteen trillion, five billion, five hundred thirty-two million, four hundred twenty-five thousand, one hundred forty-nine".