313023040171 has 2 divisors, whose sum is σ = 313023040172. Its totient is φ = 313023040170.

The previous prime is 313023040117. The next prime is 313023040181. The reversal of 313023040171 is 171040320313.

Together with previous prime (313023040117) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (171040320313) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 313023040171 - 2¹¹ = 313023038123 is a prime.

It is not a weakly prime, because it can be changed into another prime (313023040181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156511520085 + 156511520086.

It is an arithmetic number, because the mean of its divisors is an integer number (156511520086).

Almost surely, 2^313023040171 is an apocalyptic number.

313023040171 is a deficient number, since it is larger than the sum of its proper divisors (1).

313023040171 is an equidigital number, since it uses as much as digits as its factorization.

313023040171 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1512, while the sum is 25.

Adding to 313023040171 its reverse (171040320313), we get a palindrome (484063360484).

The spelling of 313023040171 in words is "three hundred thirteen billion, twenty-three million, forty thousand, one hundred seventy-one".