313023040117 has 2 divisors, whose sum is σ = 313023040118. Its totient is φ = 313023040116.

The previous prime is 313023040097. The next prime is 313023040171. The reversal of 313023040117 is 711040320313.

Together with next prime (313023040171) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 307014619921 + 6008420196 = 554089^2 + 77514^2 .

It is a cyclic number.

It is not a de Polignac number, because 313023040117 - 2³¹ = 310875556469 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 313023040091 and 313023040100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (313023040717) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156511520058 + 156511520059.

It is an arithmetic number, because the mean of its divisors is an integer number (156511520059).

Almost surely, 2^313023040117 is an apocalyptic number.

It is an amenable number.

313023040117 is a deficient number, since it is larger than the sum of its proper divisors (1).

313023040117 is an equidigital number, since it uses as much as digits as its factorization.

313023040117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1512, while the sum is 25.

The spelling of 313023040117 in words is "three hundred thirteen billion, twenty-three million, forty thousand, one hundred seventeen".