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313100102120093 is a prime number
BaseRepresentation
bin100011100110000110100110…
…0010111011011001010011101
31112001121002002110020200210222
41013030031030113123022131
5312014313002120320333
63025524111244411125
7122643510260312261
oct10714151427331235
91461532073220728
10313100102120093
119084400a164692
122b148a92846aa5
131059229caa6452
1457461a92a20a1
15262e6bb1a3298
hex11cc34c5db29d

313100102120093 has 2 divisors, whose sum is σ = 313100102120094. Its totient is φ = 313100102120092.

The previous prime is 313100102120081. The next prime is 313100102120129. The reversal of 313100102120093 is 390021201001313.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 170839068173764 + 142261033946329 = 13070542^2 + 11927323^2 .

It is a cyclic number.

It is not a de Polignac number, because 313100102120093 - 24 = 313100102120077 is a prime.

It is a super-3 number, since 3×3131001021200933 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (313100102120023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156550051060046 + 156550051060047.

It is an arithmetic number, because the mean of its divisors is an integer number (156550051060047).

Almost surely, 2313100102120093 is an apocalyptic number.

It is an amenable number.

313100102120093 is a deficient number, since it is larger than the sum of its proper divisors (1).

313100102120093 is an equidigital number, since it uses as much as digits as its factorization.

313100102120093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 26.

The spelling of 313100102120093 in words is "three hundred thirteen trillion, one hundred billion, one hundred two million, one hundred twenty thousand, ninety-three".