313100113 has 2 divisors, whose sum is σ = 313100114. Its totient is φ = 313100112.

The previous prime is 313100111. The next prime is 313100119. The reversal of 313100113 is 311001313.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 275792449 + 37307664 = 16607^2 + 6108^2 .

It is a cyclic number.

It is not a de Polignac number, because 313100113 - 2¹ = 313100111 is a prime.

It is a super-2 number, since 2×313100113² = 196063361521225538, which contains 22 as substring.

Together with 313100111, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 313100093 and 313100102.

It is not a weakly prime, because it can be changed into another prime (313100111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156550056 + 156550057.

It is an arithmetic number, because the mean of its divisors is an integer number (156550057).

Almost surely, 2^313100113 is an apocalyptic number.

It is an amenable number.

313100113 is a deficient number, since it is larger than the sum of its proper divisors (1).

313100113 is an equidigital number, since it uses as much as digits as its factorization.

313100113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27, while the sum is 13.

The square root of 313100113 is about 17694.6351474112. The cubic root of 313100113 is about 679.0385149970.

Adding to 313100113 its reverse (311001313), we get a palindrome (624101426).

The spelling of 313100113 in words is "three hundred thirteen million, one hundred thousand, one hundred thirteen".