Base | Representation |
---|---|
bin | 1011101010011111… |
… | …0111000011110000 |
3 | 22002012112212001221 |
4 | 2322213313003300 |
5 | 22403014330222 |
6 | 1234404234424 |
7 | 140406104602 |
oct | 27247670360 |
9 | 8065485057 |
10 | 3131011312 |
11 | 1367413160 |
12 | 73469ba14 |
13 | 3ab895420 |
14 | 219b8b172 |
15 | 134d220c7 |
hex | ba9f70f0 |
3131011312 has 160 divisors (see below), whose sum is σ = 7630386624. Its totient is φ = 1222656000.
The previous prime is 3131011277. The next prime is 3131011313. The reversal of 3131011312 is 2131101313.
It is a super-2 number, since 2×31310113122 = 19606463671743922688, which contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (16).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3131011313) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3928098 + ... + 3928894.
Almost surely, 23131011312 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 3131011312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3815193312).
3131011312 is an abundant number, since it is smaller than the sum of its proper divisors (4499375312).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3131011312 is a wasteful number, since it uses less digits than its factorization.
3131011312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 947 (or 941 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 16.
The square root of 3131011312 is about 55955.4404146728. The cubic root of 3131011312 is about 1462.9457184046.
Adding to 3131011312 its reverse (2131101313), we get a palindrome (5262112625).
Subtracting from 3131011312 its reverse (2131101313), we obtain a palindrome (999909999).
It can be divided in two parts, 313101 and 1312, that added together give a palindrome (314413).
The spelling of 3131011312 in words is "three billion, one hundred thirty-one million, eleven thousand, three hundred twelve".
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