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313110311200013 is a prime number
BaseRepresentation
bin100011100110001011010110…
…0110111111110010100001101
31112001122001102221102200200002
41013030112230313332110031
5312014444404131400023
63025532520300414045
7122644321254126545
oct10714265467762415
91461561387380602
10313110311200013
11908483789a3518
122b14aa61847325
1310593238ba9a42
1457468970cc325
15262eab75b0b28
hex11cc5acdfe50d

313110311200013 has 2 divisors, whose sum is σ = 313110311200014. Its totient is φ = 313110311200012.

The previous prime is 313110311200003. The next prime is 313110311200031. The reversal of 313110311200013 is 310002113011313.

Together with next prime (313110311200031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 179323219710244 + 133787091489769 = 13391162^2 + 11566637^2 .

It is an emirp because it is prime and its reverse (310002113011313) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 313110311200013 - 216 = 313110311134477 is a prime.

It is a super-3 number, since 3×3131103112000133 (a number of 44 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (313110311200003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156555155600006 + 156555155600007.

It is an arithmetic number, because the mean of its divisors is an integer number (156555155600007).

Almost surely, 2313110311200013 is an apocalyptic number.

It is an amenable number.

313110311200013 is a deficient number, since it is larger than the sum of its proper divisors (1).

313110311200013 is an equidigital number, since it uses as much as digits as its factorization.

313110311200013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 313110311200013 its reverse (310002113011313), we get a palindrome (623112424211326).

The spelling of 313110311200013 in words is "three hundred thirteen trillion, one hundred ten billion, three hundred eleven million, two hundred thousand, thirteen".